1/5(3x^2-10)=12x

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Solution for 1/5(3x^2-10)=12x equation: 


x in (-oo:+oo)

(1/5)*(3*x^2-10) = 12*x // - 12*x

(1/5)*(3*x^2-10)-(12*x) = 0

(1/5)*(3*x^2-10)-12*x = 0

1/5*(3*x^2-10)-12*x = 0

1/5*(3*x^2-10)-12*x = 0

3/5*x^2-12*x-2 = 0

3/5*x^2-12*x-2 = 0

3/5*x^2-12*x-2 = 0

DELTA = (-12)^2-(-2*3/5*4)

DELTA = 744/5

DELTA > 0

x = ((744/5)^(1/2)+12)/(3/5*2) or x = (12-(744/5)^(1/2))/(3/5*2)

x = 5/6*((744/5)^(1/2)+12) or x = 5/6*(12-(744/5)^(1/2))

(x-5/6*(12-(744/5)^(1/2)))*(x-5/6*((744/5)^(1/2)+12)) = 0

(x-5/6*(12-(744/5)^(1/2)))*(x-5/6*((744/5)^(1/2)+12)) = 0

( x-5/6*((744/5)^(1/2)+12) )

x-5/6*((744/5)^(1/2)+12) = 0 // + -5/6*((744/5)^(1/2)+12)

x = -(-5/6*((744/5)^(1/2)+12))

x = 5/6*((744/5)^(1/2)+12)

( x-5/6*(12-(744/5)^(1/2)) )

x-5/6*(12-(744/5)^(1/2)) = 0 // + -5/6*(12-(744/5)^(1/2))

x = -(-5/6*(12-(744/5)^(1/2)))

x = 5/6*(12-(744/5)^(1/2))

x in { 5/6*((744/5)^(1/2)+12), 5/6*(12-(744/5)^(1/2)) }

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